method
include?
include?(p1)
public
Returns true if the given object is present in self (that is, if any object == anObject), false otherwise.
a = [ "a", "b", "c" ] a.include?("b") #=> true a.include?("z") #=> false
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mindloaf -
May 2, 2009
4 thanks
Test if one array includes the elements of another
You can just use a set difference (aka minus) to see if one array includes all elements of another
not_included = [1,2,3] - (1..9).to_a not_included # => [] not_included = [1,2,3,'A'] - (1..9).to_a not_included # => ["A"]
Use intersection to test if any of the one are in the other:
shared = [1,2,3,'A'] & (1..9).to_a shared # => [1, 2, 3]
anoiaque -
June 22, 2012 - (v1_8_6_287 - v1_9_3_125)
3 thanks
Test if an array is included in another
Array
class Array def included_in? array array.to_set.superset?(self.to_set) end end [1,2,4].included_in?([1,10,2,34,4]) #=> true
mutru -
February 24, 2009
2 thanks
Test if one array includes the elements of another v2
Maybe a bit more readable way to write the previous snippet would’ve been
puts "yay" if [1, 2, 3].all? { |i| (1..9).include?(i) } # => "yay" puts "nope" if [1, 2, 3, 'A'].any? { |i| not (1..9).include?(i) } # => "nope"
Overbryd -
February 24, 2009
0 thanks
colmac -
November 15, 2013
0 thanks
Test if an array is included in another
a note for anoiaque solution…
before running you need to require set
require 'set' class Array def included_in? array array.to_set.superset(self.to_set) end end [1,2,4].included_in?([1,10,2,34,4]) #=> true